If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2-10x-117=0
a = 3; b = -10; c = -117;
Δ = b2-4ac
Δ = -102-4·3·(-117)
Δ = 1504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1504}=\sqrt{16*94}=\sqrt{16}*\sqrt{94}=4\sqrt{94}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-4\sqrt{94}}{2*3}=\frac{10-4\sqrt{94}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+4\sqrt{94}}{2*3}=\frac{10+4\sqrt{94}}{6} $
| 4x-2.1=5.6 | | 7x/2x=8 | | 10+3/2x+1/5=15 | | 78=5(a-2)+6(3a+7) | | 1050-25w=400+75w | | 19=2n-8+7n | | 5=0,2-0,0129xX-0,00184xX^2+0,000214xX^3-0,0000056xX^4 | | x−19=2 | | 7x+6=24+x | | 12b=(-12b) | | 7x+6=24*x | | 23=-3r-1 | | 5(20x+50)=1,250 | | 2(4–2r)=-2(r+5 | | 5.95x=5.15x+4.8 | | 1.50r+15.00=2.25r | | 2+.40x=12.8x-1 | | h+6/(5)=2 | | 4x8-17/5-3=25.6 | | a/(3)+4=6 | | 3+3p-7=2/3(p+2) | | 1.9=4.7-0.7x | | 3x+1/5=x-2/10 | | 1=a=2 | | 3.4x=x=5.3 | | -y+6-2y=3(y+6) | | 20-3x=-5 | | (6+3/4x)=(1/2x-4) | | 12r2-11r-15=0 | | 3x²+x-30=0 | | 0,2-0,0129x5-0,00184x5^2+0,000214x5^3-0,0000056x5^4=0 | | 2(1.25)^x=4 |